/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/
#include<stdio.h>
main()
{
int n,i,f=1;
scanf("%d",&n);
for(i=n;i>=1;i--)
{
f=f*i;
}
printf("%d\n",f);
return 0;
}
//Happy_Coding
#include<stdio.h>
main()
{
int n,i,f=1;
scanf("%d",&n);
for(i=n;i>=1;i--)
{
f=f*i;
}
printf("%d\n",f);
return 0;
}
//Happy_Coding