CodeLover: October 2018

Monday, October 29, 2018

1 bit adder using X-OR gate in VIPLE

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/ //Happy_Coding

1 bit adder using X-OR gate in VIPLE

1 bit adder using basic gate in VIPLE

X-OR GATE using custom activity in VIPLE

NOT GATE using custom activity in VIPLE

AND GATE using custom activity in VIPLE

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/ //Happy_Coding

OR GATE using custom activity in VIPLE

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/ //Happy_Coding

Friday, October 26, 2018

Welcome to HPU using VIPLE

Welcome

Finding the Area of a triangle using VIPLE

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/ //Happy_Coding

Area of a triangle

Hello world Using Viple

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/ //Happy_Coding

Hello world

Uri 1149 Solution in C | Summing Consecutive Integers

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>
int main()
{
int X, N, a,b=0;
scanf("%d %d", &X, &N);
while(N<=0)
scanf("%d", &N);
for(a=1; a<=N; a++)
{
b+=X;
X++;
}
printf("%d\n",b);
return 0;
}
//Happy_Coding

Uri 1146 solution in C | Growing Sequences

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int x,i;
while(1)
{
scanf("%d",&x);
if(x==0)
break;
for(i=1;i<x;i++)
{
printf("%d ",i);
}
printf("%d\n",x);

}
return 0;
}

//Happy_Coding

Uri 1145 solution in C | Logical Sequence 2

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
int main()
{
int n,a,i,j,k,l,m=1;
scanf("%d %d",&a,&n);
k = n / a;
l=a;
for(i = 1;i <=k;i++)
{
printf("%d",m);
for(j=m+1;j<=l;j++){
printf(" %d",j);
}
printf("\n");
m += a;
l += a;
}
return 0;
}

//Happy_Coding

Uri 1144 solution in C | Logical Sequence

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int i,a,b,c,n,x,y,z;
scanf("%d",&n);
for(i=1;i<=n;i++)
{
a=i;
b=i*i;
c=i*i*i;
x=b+1;
y=c+1;
printf("%d %d %d\n%d %d %d\n",i,b,c,a,x,y);

}
return 0;
}

//Happy_Coding

Uri 1143 solution in C | Squared and Cubic

//Happy_Coding

Uri 1142 solution in C | PUM

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>
int main()
{
int N, a,b,c=1,d=4;
scanf("%d", &N);
for(a=1;a<=N;a++)
{
for(b=c;b<=d;b++)
{
if(b%4==0)
printf("PUM\n");
else
printf ("%d ",b);
}
c+=4; d+=4;
}
return 0;
}

//Happy_Coding

Uri 1134 solution in C | Type of Fuel

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int a,x=0,y=0,z=0;
while(1)
{
scanf("%d",&a);
if(a==4)
break;
else
{
if(a==1)
{
x++;
}
else if(a==2)
{
y++;
}
else if(a==3)
{
z++;
}
else
continue;
}
}
printf("MUITO OBRIGADO\nAlcool: %d\nGasolina: %d\nDiesel: %d\n",x,y,z);
return 0;
}

//Happy_Coding

Uri 1133 solution in C | Rest of a Division

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int x,y,i;
scanf("%d%d",&x,&y);
if(x>y)
{
for(i=y+1;i<x;i++)
{
if(i%5==2||i%5==3)
printf("%d\n",i);
}
}
else if(y>x)
{
for(i=x+1;i<y;i++)
{
if(i%5==2||i%5==3)
printf("%d\n",i);
}
}
return 0;
}

//Happy_Coding

Uri 1132 solution in C | Multiples of 13

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int x,y,i,sum=0;
scanf("%d%d",&x,&y);
if(x>y)
{
for(i=y;i<=x;i++)
{
if(i%13!=0)
{
sum=sum+i;
}
}
}
else if(y>x)
{

for(i=x;i<=y;i++)
{
if(i%13!=0)
{
sum=sum+i;
}
}

}
printf("%d\n",sum);
return 0;
}

//Happy_Coding

Uri 1118 solution in C | Several Scores with Validation

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>
int main()
{
double a,b,c,d,e,f,g,h=1,x=1,y=1,z=1;
for(h=1;;h=1,x=1,y=1,z=1)
{
scanf("%lf",&a);
if(a<0 || a>10)
{
printf("nota invalida\n");
continue;
}
while(x==1)
{
scanf("%lf",&b);
if(b<0 || b>10)
{
printf("nota invalida\n");
continue;
}
x+=2;
}
c=(a+b)/2.0;
printf("media = %.2lf\n",c);
printf("novo calculo (1-sim 2-nao)\n");
while(y==1)
{
scanf("%lf", &g);
if(g<1 || g>2)
{
printf("novo calculo (1-sim 2-nao)\n");
continue;
}
y+=2;
}
if(g==2)
break;
}
return 0;
}
//Happy_Coding

Uri 1117 solution in C | Score Validation

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>
int main()
{
double a,b,c=0,d=0;
while(1)
{
if(d==2)
break;
scanf("%lf", &a);
if(a>=0 && a<=10)
{
d++;
c+=a;
}
else
printf("nota invalida\n");
}
b=c/2.00;
printf("media = %.2lf\n", b);
return 0;
}

//Happy_Coding

Uri 1116 solution in C | Dividing X by Y

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int x,y,n,i;
double t;
scanf("%d",&n);
for(i=1;i<=n;i++)
{
scanf("%d%d",&x,&y);
if(y==0)
{
printf("divisao impossivel\n");
}
else
{
t=x/(y*1.00);
printf("%.1lf\n",t);
}

}
return 0;

}

//Happy_Coding

Uri 1115 solution in C | Quadrant

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int m,n;
while(1)
{
scanf("%d%d",&m,&n);
if(m==0||n==0)
break;
else if(m>0&&n>0)
{
printf("primeiro\n");
}
else if(m>0&&n<0)
{
printf("quarto\n");
}
else if(m<0&&n>0)
{
printf("segundo\n");
}
else if(m<0&&n<0)
{
printf("terceiro\n");
}
}
return 0;
}

//Happy_Coding

Uri 1114 soution in C | Fixed Password

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int i;
while(1)
{
scanf("%d",&i);
if(i==2002)
{
printf("Acesso Permitido\n");
break;
}
else if(i!=2002)
{
printf("Senha Invalida\n");
}

}
return 0;
}

//Happy_Coding

Uri 1113 solution in C | Ascending and Descending

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int i,j;
while(1)
{
scanf("%d%d",&i,&j);
if(i==j)
break;
else if(i>j)
{
printf("Decrescente\n");
}
else if(j>i)
{
printf("Crescente\n");
}
}
return 0;
}

//Happy_Coding

Uri 1101 solution in C | Sequence of Numbers and Sum

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int m,n,i,j=0;
while(1)
{
scanf("%d%d",&m,&n);
if(m<=0||n<=0)
{
break;
}
else if(m>n)
{
for(i=n,j=0;i<=m;i++)
{
j=j+i;
printf("%d ",i);
}
printf("Sum=%d\n",j);
}
else if(n>m)
{
for(i=m,j=0;i<=n;i++)
{
j=j+i;
printf("%d ",i);
}
printf("Sum=%d\n",j);
}

}
return 0;

}

//Happy_Coding

Uri 1099 solution in C | Sum of Consecutive Odd Numbers II

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int i,j,k,l=0,x,y,n;
scanf("%d",&n);
for(i=1;i<=n;i++)
{
scanf("%d%d",&x,&y);
if(x>y)
{
for(j=y+1,l=0;j<x;j++)
{

if(j%2!=0)
{
l=l+j;

}

}
printf("%d\n",l);

}
else
{
for(j=x+1,l=0;j<y;j++)
{

if(j%2!=0)
{
l=l+j;

}

}
printf("%d\n",l);

}

}
return 0;

}

//Happy_Coding

Uri 1098 solution in C | Sequence IJ 4

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>
int main()
{
double a,b,c=1,d=3,e,f;
int x;
for(a=0; a<=1.9; a=a+.2)
{
for(b=1.0; b<=3.0; b++)
{
e=b+a;
if(a==0.0||a==1.0) printf("I=%.0lf J=%.0lf",a,e);
else if(e==3.0||e==4.0||e==5.0) printf("I=%.0lf J=%.0lf",a,e);
else printf("I=%.1lf J=%.1lf",a,e);
printf("\n");
}
}
for(x=3; x<=5; x++) printf("I=2 J=%d\n",x);
return 0;
}

//Happy_Coding

Uri 1097 solution in C | Sequence IJ 3

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int i,j,k=7;
for(i=1;i<=9;i=i+2)
{
for(j=k;j>=k-2;j--)
{
printf("I=%d J=%d\n",i,j);

}
k+=2;
}
return 0;
}

//Happy_Coding

Uri 1096 solution in C | Sequence IJ 2

Uri 1095 solution in C | Sequence IJ 1

//Happy_Coding

Uri 1094 Solution in C | Experiments

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>
int main()
{
int a,b,c,d=0,e=0,f=0,g;
double x,y,z;
char m[2];
scanf("%d", &a);
for(b=1; b<=a; b++)
{
scanf("%d%s",&c,&m);
if(m[0]=='C') d+=c;
else if(m[0]=='R') e+=c;
else if(m[0]=='S') f+=c;
}
g=d+e+f;
x=(d/(g*1.0))*100.00;
y=(e/(g*1.0))*100.00;
z=(f/(g*1.0))*100.00;
printf("Total: %d cobaias\n",g);
printf("Total de coelhos: %d\n",d);
printf("Total de ratos: %d\n",e);
printf("Total de sapos: %d\n",f);
printf("Percentual de coelhos: %.2lf %%\n",x);
printf("Percentual de ratos: %.2lf %\n",y);
printf("Percentual de sapos: %.2lf %\n",z);
return 0;
}

//Happy_Coding

Uri 1080 solution in C | Highest and Position

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int n=0,i,a,max=0,j;
for(i=1;i<=100;i++)
{
scanf("%d",&a);
n++;
if(a>max)
{
max=a;
j=n;
}
}
printf("%d\n%d\n",max,j);
return 0;
}

//Happy_Coding

Uri 1079 solution in C | Weighted Averages

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int n,i;
double k,m,b,s;
scanf("%d",&n);
for(i=1;i<=n;i++)
{
scanf("%lf%lf%lf",&k,&m,&b);
s=((k*2)+(m*3)+(b*5))/10;
printf("%.1lf\n",s);

}
return 0;
}

//Happy_Coding

Uri 1078 solution in C | Multiplication Table

//Happy_Coding

Uri 1075 solution in C | Remaining 2

Uri 1074 solution in C | Even or Odd

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>
int main()
{
int N,X,a;
scanf ("%d", &N);
for(a=1;a<=N;a++)
{
scanf ("%d",&X);
if(X==0)
printf("NULL\n");
else if(X<=0&&X%2==0)
printf ("EVEN NEGATIVE\n");
else if(X<=0&&X%2==-1)
printf ("ODD NEGATIVE\n");
else if(X>=0&&X%2==0)
printf ("EVEN POSITIVE\n");
else if(X>=0&&X%2==1)
printf ("ODD POSITIVE\n");
}
return 0;
}

//Happy_Coding

Uri 1073 solution in C | Even Square

//Happy_Coding

Uri 1072 solution in C | Interval 2

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int n,i,a,in=0,out=0;
scanf("%d",&n);
for(i=0;i<n;i++)
{
scanf("%d",&a);
if(a>=10&&a<=20)
{
in++;
}
else
out++;

}
printf("%d in\n%d out\n",in,out);
return 0;
}

//Happy_Coding

Uri 1071 solution in C | Sum of Consecutive Odd Numbers I

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int a,b,i,s=0;
scanf("%d%d",&a,&b);
if(a>b)
{
for(i=b+1;i<a;i++)
{

if(i%2!=0)
{
s=s+i;
}
}
}
else
{
for(i=a+1;i<b;i++)
{

if(i%2!=0)
{
s=s+i;
}
}
}
printf("%d\n",s);
return 0;
}

//Happy_Coding

Uri 1070 solution in C | Six Odd Numbers

//Happy_Coding

Uri 1067 solution in C | Odd Numbers

//Happy_Coding

Uri 1066 solution in C | Even, Odd, Positive and Negative

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int n,i,p=0,ne=0,e=0,o=0;
for(i=0;i<5;i++)
{
scanf("%d",&n);
if(n%2==0)
{
e++;
}
if(n%2!=0)
{
o++;
}
if(n>0)
{
p++;
}
if(n<0)
{
ne++;
}

}
printf("%d valor(es) par(es)\n%d valor(es) impar(es)\n%d valor(es) positivo(s)\n%d valor(es) negativo(s)\n",e,o,p,ne);
return 0;
}

//Happy_Coding

Uri 1065 solution in C | Even Between five Numbers

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int n,c=0,i;
for(i=0;i<5;i++)
{
scanf("%d",&n);
if(n%2==0)
{
c++;
}
}
printf("%d valores pares\n",c);
return 0;
}

//Happy_Coding

Uri 1064 solution in C | Positives and Average

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int i,c=0;
float s=0,a,n;
for(i=0;i<6;i++)
{
scanf("%f",&n);

if(n>0)
{
s=s+n;
c++;
}
}

a=s/c;
printf("%d valores positivos\n",c);
printf("%.1f\n",a);
return 0;
}

//Happy_Coding

Uri 1060 solution in C | Positive Numbers

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
double n,i,j=0;
for(i=0;i<6;i++)
{
scanf("%lf",&n);
if(n>0)
{
j++;

}
}
printf("%.0lf valores positivos\n",j);
return 0;

}

//Happy_Coding

Uri 1059 solution in C | Even numbers

//Happy_Coding

Uri 1052 solution in C | Month

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int n;
scanf("%d",&n);
if(n==1)
{
printf("January\n");
}
else if(n==2)
{
printf("February\n");
}
else if(n==3)
{
printf("March\n");
}
else if(n==4)
{
printf("April\n");
}
else if(n==5)
{
printf("May\n");
}
else if(n==6)
{
printf("June\n");
}
else if(n==7)
{
printf("July\n");
}
else if(n==8)
{
printf("August\n");
}
else if(n==9)
{
printf("September\n");
}
else if(n==10)
{
printf("October\n");
}
else if(n==11)
{
printf("November\n");
}
else if(n==12)
{
printf("December\n");
}
return 0;
}

//Happy_Coding

Uri 1051 solution in C | Taxes

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
double n,s,s1;
scanf("%lf",&n);
if(n>0&&n<=2000)
{
printf("Isento\n");
}
else if(n>2000&&n<=3000)
{
s1=n-2000;
s=s1*.08;
printf("R$ %.2lf\n",s);
}
else if(n>3000&&n<=4500)
{
s1=n-3000;
s=80+(s1*.18);
printf("R$ %.2lf\n",s);
}
else if(n>4500)
{
s1=n-4500;
s=350+(s1*.28);
printf("R$ %.2lf\n",s);
}
return 0;
}

//Happy_Coding

Uri 1050 solution in C | DDD

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>
int main()
{
int N;
scanf("%d",&N);
if(N==61)
printf("Brasilia\n");
else if(N==71)
printf("Salvador\n");
else if(N==11)
printf("Sao Paulo\n");
else if(N==21)
printf("Rio de Janeiro\n");
else if(N==32)
printf("Juiz de Fora\n");
else if(N==19)
printf("Campinas\n");
else if(N==27)
printf("Vitoria\n");
else if(N==31)
printf("Bela Horizonte\n");
else
printf("DDD nao cadastrado\n");
return 0;
}
//Happy_Coding

Uri 1048 solution in C | Salary Increase

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/
#include<stdio.h>
main()
{
float m,s,si;
scanf("%f",&m);
if(m>=0&&m<=400)
{
si=m*.15;
s=m+si;

printf("Novo salario: %.2f\nReajuste ganho: %.2f\nEm percentual: 15 %\n",s,si);
}
else if(m>400&&m<=800)
{
si=m*.12;
s=m+si;

printf("Novo salario: %.2f\nReajuste ganho: %.2f\nEm percentual: 12 %\n",s,si);
}
else if(m>800&&m<=1200)
{
si=m*.10;
s=m+si;

printf("Novo salario: %.2f\nReajuste ganho: %.2f\nEm percentual: 10 %\n",s,si);
}
else if(m>1200&&m<=2000)
{
si=m*.07;
s=m+si;

printf("Novo salario: %.2f\nReajuste ganho: %.2f\nEm percentual: 7 %\n",s,si);
}
else if(m>2000)
{
si=m*.04;
s=m+si;

printf("Novo salario: %.2f\nReajuste ganho: %.2f\nEm percentual: 4 %\n",s,si);
}

}

//Happy_Coding

Uri 1047 Solution in C | Game Time with Minutes

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>
int main()
{
int start_h, end_h, start_m, end_m, duration_h, duration_m;
scanf("%d %d %d %d", &start_h, &start_m, &end_h, &end_m);

duration_h = end_h - start_h;

if (duration_h < 0)
{
duration_h = 24 + (end_h - start_h);
}

duration_m = end_m - start_m;
if (duration_m < 0)

{
duration_m = 60 + (end_m - start_m);
duration_h--;
}

if (start_h == end_h && start_m == end_m)

{
printf("O JOGO DUROU 24 HORA(S) E 0 MINUTO(S)\n");
}
else printf("O JOGO DUROU %d HORA(S) E %d MINUTO(S)\n", duration_h, duration_m);
return 0;

}
//Happy_Coding

Uri 1046 Solution in C | Game Time

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>

int main()

{

int st, et, rt;

scanf("%d %d", &st, &et);

rt = et - st;

if (rt < 0)

{

rt = 24 + (et - st);

}

if (st == et)

{

printf("O JOGO DUROU 24 HORA(S)\n");

}

else printf("O JOGO DUROU %d HORA(S)\n", rt);

return 0;

}

//Happy_Coding

Uri 1045 solution in C | Triangle Types

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>

int main()

{

double a, b, c, temp;

scanf("%lf %lf %lf", &a, &b, &c);

if (a < b)

{

temp = a;

a = b;

b = temp;

}

if (b < c)

{

temp = b;

b = c;

c = temp;

}

if (a < b)

{

temp = a;

a = b;

b = temp;

}

if (a >= b + c)

{

printf("NAO FORMA TRIANGULO\n");

}

else if (a * a == b * b + c * c)

{

printf("TRIANGULO RETANGULO\n");

}

else if (a * a > b * b + c * c)

{

printf("TRIANGULO OBTUSANGULO\n");

}

else if (a * a < b * b + c * c)

{

printf("TRIANGULO ACUTANGULO\n");

}

if (a == b && b == c)

{

printf("TRIANGULO EQUILATERO\n");

}

else if (a == b || b == c)

{

printf("TRIANGULO ISOSCELES\n");

}

return 0;

}

//Happy_Coding

Uri 1044 Solution in C | Multiples

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int x,y;
scanf("%d%d",&x,&y);
if(y%x==0||x%y==0)
{
printf("Sao Multiplos\n");
}
else

{
printf("Nao sao Multiplos\n");
}
return 0;
}

//Happy_Coding

Uri 1043 Solution in C | Triangle

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
float a,b,c,p,area;
scanf("%f%f%f",&a,&b,&c);
if((a+b)>c&&(b+c)>a&&(c+a)>b)
{
p=a+b+c;
printf("Perimetro = %.1f\n",p);
}
else
{
area=0.5*(a+b)*c;
printf("Area = %.1f\n",area);
}
return 0;
}

//Happy_Coding

Uri 1042 solution in C | Simple Sort

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int a,b,c,min,max,mid;
scanf("%d%d%d",&a,&b,&c);
min=a;
if(b<c&&b<a)
{
min=b;
}
else if(c<a&&c<b)
{
min=c;
}
mid=a;
if(b<a&&b>c||b>a&&b<c)
{
mid=b;
}
else if(c>a&&c<b||c<a&&c>b)
{
mid=c;
}
max=a;
if(b>c&&b>a)
{
max=b;
}
else if(c>a&&c>b)
{
max=c;
}
printf("%d\n%d\n%d\n\n",min,mid,max);
printf("%d\n%d\n%d\n",a,b,c);
return 0;
}

//Happy_Coding

Uri 1041 solution in C | Coordinates of a Point

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
float x,y;
scanf("%f%f",&x,&y);
if(x==0&&y==0)
{
printf("Origem\n");
}
else if(x==0&&y!=0)
{
printf("Eixo Y\n");
}
else if(y==0&&x!=0)
{
printf("Eixo X\n");
}
else if(x>0&&y>0)
{
printf("Q1\n");
}
else if(x>0&&y<0)
{
printf("Q4\n");
}
else if(x<0&&y>0)
{
printf("Q2\n");
}
else if(x<0&&y<0)
{
printf("Q3\n");
}
return 0;
}

//Happy_Coding

Uri 1040 solution in C | Average 3

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
float n1,n2,n3,n4,m,t;
scanf("%f%f%f%f",&n1,&n2,&n3,&n4);
m=((n1*2)+(n2*3)+(n3*4)+(n4*1))/10;
printf("Media: %.1f\n",m);
if(m>=7)
{
printf("Aluno aprovado.\n");
}
else if(m<5)
{
printf("Aluno reprovado.\n");
}
else if(m>=5&&m<7)
{
printf("Aluno em exame.\n");
float d,r;
scanf("%f",&d);
printf("Nota do exame: %.1f\n",d);
r=(m+d)/2;
if(r>=5)
{
printf("Aluno aprovado.\n");
}
else if(r<5)
{
printf("Aluno reprovado.\n");
}
printf("Media final: %.1f\n",r);
}
return 0;
}

//Happy_Coding

Uri 1038 solution in C | Snack

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int x,y;
float z;
scanf("%d%d",&x,&y);
if(x==1)
{
z=y*4;
}
else if(x==2)
{
z=y*4.5;
}
else if(x==3)
{
z=y*5;
}
else if(x==4)
{
z=y*2;
}
else if(x==5)
{
z=y*1.5;
}
printf("Total: R$ %.2f\n",z);
return 0;
}

//Happy_Coding

Uri 1037 solution in C | Interval

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
float x;
scanf("%f",&x);
if(x<0||x>100)
{
printf("Fora de intervalo\n");
}
else if(x>=0&&x<=25)
{
printf("Intervalo [0,25]\n");
}
else if(x>=25&&x<=50)
{
printf("Intervalo (25,50]\n");
}
else if(x>=50&&x<=75)
{
printf("Intervalo (50,75]\n");
}
else if(x>=75&&x<=100)
{
printf("Intervalo (75,100]\n");
}
else
printf("Fora de intervalo\n");
return 0;
}

//Happy_Coding

Uri 1021 solution in C | Banknotes and Coins

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>

int main() {
int n100, n50, n20, n10, n5, n2;
int m1, m50, m25, m10, m05, m01;
double n;

scanf("%lf", &n);
int notas = n;
int moedas = (n - notas) * 100;

if((moedas * 1000) % 10 == 9){
moedas++;
}

n100 = notas/100;
notas = notas%100;
n50 = notas/50;
notas = notas%50;
n20 = notas/20;
notas = notas%20;
n10 = notas/10;
notas = notas%10;
n5 = notas/5;
notas = notas%5;
n2 = notas/2;
notas = notas%2;

m1 = notas/1;
notas = notas%1;
m50 = moedas/50;
moedas = moedas%50;
m25 = moedas/25;
moedas = moedas%25;
m10 = moedas/10;
moedas = moedas%10;
m05 = moedas/5;
moedas = moedas%5;
m01 = moedas/1;

printf("NOTAS:\n");

printf("%d nota(s) de R$ 100.00\n", n100);
printf("%d nota(s) de R$ 50.00\n", n50);
printf("%d nota(s) de R$ 20.00\n", n20);
printf("%d nota(s) de R$ 10.00\n", n10);
printf("%d nota(s) de R$ 5.00\n", n5);
printf("%d nota(s) de R$ 2.00\n", n2);

printf("MOEDAS:\n");

printf("%d moeda(s) de R$ 1.00\n", m1);
printf("%d moeda(s) de R$ 0.50\n", m50);
printf("%d moeda(s) de R$ 0.25\n", m25);
printf("%d moeda(s) de R$ 0.10\n", m10);
printf("%d moeda(s) de R$ 0.05\n", m05);
printf("%d moeda(s) de R$ 0.01\n", m01);

return 0;

}

//Happy_Coding

Uri 1036 Solution in C | Bhaskara's Formula

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
float a,b,c,x,y;
scanf("%f%f%f",&a,&b,&c);
if(((b*b)-(4*a*c))<0||a==0)
{
printf("Impossivel calcular\n");
}
else
{
x=((-b)+pow(((b*b)-(4*a*c)),0.5))/(2*a);
y=((-b)-pow(((b*b)-(4*a*c)),0.5))/(2*a);
printf("R1 = %.5f\nR2 = %.5f\n",x,y);
}

return 0;

}

//Happy_Coding

Uri 1035 solution in C | Selection Test 1

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int a,b,c,d;
scanf("%d%d%d%d",&a,&b,&c,&d);
if(b>c&&d>a&&(c+d)>(a+b)&&(c&&d)>=0&&a%2==0)
{
printf("Valores aceitos\n");
}
else
printf("Valores nao aceitos\n");
return 0;
}

//Happy_Coding

Uri 1020 solution in C | Age in Days

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int n,y,m,d,n1,n2;
scanf("%d",&n);
y=n/365;
n1=n%365;
m=n1/30;
n2=n1%30;
d=n2;
printf("%d ano(s)\n%d mes(es)\n%d dia(s)\n",y,m,d);
return 0;
}

//Happy_Coding

Uri 1018 Solution in C | Banknotes

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>
int main()
{
int n;
scanf("%d", &n);
printf("%d\n", n);
printf("%d nota(s) de R$ 100,00\n", n/100);
n %= 100;
printf("%d nota(s) de R$ 50,00\n", n/50);
n %= 50;
printf("%d nota(s) de R$ 20,00\n", n/20);
n %= 20;
printf("%d nota(s) de R$ 10,00\n", n/10);
n %= 10;
printf("%d nota(s) de R$ 5,00\n", n/5);
n %= 5;
printf("%d nota(s) de R$ 2,00\n", n/2);
n %= 2;
printf("%d nota(s) de R$ 1,00\n", n);
return 0;
}
//Happy_Coding

Uri 1019 solution in C | Time Conversion

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int n,h,m,s,n1,n2;
scanf("%d",&n);
h=n/3600;
n1=n%3600;
m=n1/60;
n2=n1%60;
s=n2;
printf("%d:%d:%d\n",h,m,s);
return 0;
}

//Happy_Coding

Uri 1017 Solution in C | Fuel Spent

//Happy_Coding

Uri 1016 solution in C | Distance

//Happy_Coding

Uri 1015 solution in C | Distance Between Two Points

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
#include<math.h>
main()
{
double x1,y1,x2,y2,d;
scanf("%lf%lf%lf%lf",&x1,&y1,&x2,&y2);
d=sqrt(((y2-y1)*(y2-y1))+((x2-x1)*(x2-x1)));

printf("%.4lf\n",d);
return 0;
}

//Happy_Coding

Uri 1014 solution in C | Consumption

//Happy_Coding

Uri 1013 solution in C | The Greatest

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int a,b,c,MAIRORAB,mairor;
scanf("%d%d%d",&a,&b,&c);
MAIRORAB=((a+b)+abs(a-b))/2;
mairor=((MAIRORAB+c)+abs(MAIRORAB-c))/2;
printf("%d eh o maior\n",mairor);
return 0;

}

//Happy_Coding

Uri 1012 solution | Area

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
double a,b,c,x,y,z,r,s,pi=3.14159;
scanf("%lf%lf%lf",&a,&b,&c);
x=0.5*a*c;
y=pi*c*c;
z=0.5*(a+b)*c;
r=b*b;
s=a*b;
printf("TRIANGULO: %.3f\nCIRCULO: %.3f\nTRAPEZIO: %.3f\nQUADRADO: %.3f\nRETANGULO: %.3f\n",x,y,z,r,s);
return 0;
}

//Happy_Coding

Uri 1011 solution | Sphere

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
double r,v,pi=3.14159;
scanf("%lf",&r);
v=((4.0/3.0)*(pi)*(r*r*r));
printf("VOLUME = %.3lf\n",v);
return 0;
}

//Happy_coding

Uri 1010 solution in C | Simple Calculate

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int c1,c2,a1,a2;
float p1,p2,total;
scanf("%d%d%f\n%d%d%f",&c1,&a1,&p1,&c2,&a2,&p2);
//scanf("%f%f%f",&c1,&a2,&p2);
total=(a1*p1)+(a2*p2);
printf("VALOR A PAGAR: R$ %.2f\n",total);
return 0;

}

//Happy_coding

Uri 1009 solution | salary with bonus

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
char name;
double sal,b,ts;
scanf("%s%lf%lf",&name,&sal,&b);
ts=sal+(b*.15);
printf("TOTAL = R$ %.2lf\n",ts);
return 0;
}

//Happy_coding

Uri 1008 Solution in C | Salary

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int n,wh;
float s,t;
scanf("%d%d%f",&n,&wh,&s);
t=wh*s;
printf("NUMBER = %d\nSALARY = U$ %.2f\n",n,t);
return 0;

}

//Happy_coding

Uri 1007 Solution in C | Difference

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
int A,B,C,D,DIFERENCA;
scanf("%d %d %d %d",&A, &B, &C, &D);
DIFERENCA=(A * B - C * D);
printf("DIFERENCA = %d\n",DIFERENCA);
return 0;
}

//Happy_coding