Uri 1050 solution in C | DDD

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include <stdio.h>
int main()
{
   int N;
    scanf("%d",&N);
    if(N==61)
        printf("Brasilia\n");
    else if(N==71)
        printf("Salvador\n");
    else if(N==11)
        printf("Sao Paulo\n");
    else if(N==21)
        printf("Rio de Janeiro\n");
    else if(N==32)
        printf("Juiz de Fora\n");
    else if(N==19)
        printf("Campinas\n");
    else if(N==27)
        printf("Vitoria\n");
    else if(N==31)
        printf("Bela Horizonte\n");
    else
        printf("DDD nao cadastrado\n");
    return 0;
}
 //Happy_Coding