Friday, October 26, 2018

Uri 1037 solution in C | Interval

/*Before seeing the code solution make sure that you have tried enough. Don’t copy- paste the whole code. Find out the logic. If you face any trouble, just inform me in comment.*/

#include<stdio.h>
main()
{
    float x;
    scanf("%f",&x);
    if(x<0||x>100)
    {
        printf("Fora de intervalo\n");
    }
    else if(x>=0&&x<=25)
    {
        printf("Intervalo [0,25]\n");
    }
     else if(x>=25&&x<=50)
    {
        printf("Intervalo (25,50]\n");
    }
     else if(x>=50&&x<=75)
    {
        printf("Intervalo (50,75]\n");
    }
     else if(x>=75&&x<=100)
    {
        printf("Intervalo (75,100]\n");
    }
    else
        printf("Fora de intervalo\n");
    return 0;
}


 //Happy_Coding

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